Thanks for your reply. @trobertson
Both Ex and Ez correspond to S polarization components i.e. normal to the plane of incidence for ky propagating light.
The plane of incidence is a plane and S polarization means that the electric field is perpendicular to the plane of incidence. So I think only one electric field component can be the S polarization. In the situation of the example on KB, the plane of incidence is XY, so I think only the Ez component can be regarded as S polarization. In the picture I uploaded above, I use a 2D-Z normal monitor. So I still don’t think that the simulation can get the reflectivity of S polarization. Am I right?
There will not be any Ez components since this is out of the plane of the dipole.
Another question is about the plane of the dipole. I am still not clear about which electric component can be generated by a dipole. I made a test like this:
In this situation, the dipole is along y-axis(phase = 0, theta = 90, phi = 90). I use a monitor of 2D-Z normal to get the electric field. Ex and Ey component are not zero, Ez is zero.
In this situation, the the dipole is along x-axis(phase = 0, theta = 90, phi = 0). I use a monitor of 2D-Z normal to get the electric field. I can get Ex and Ey component are not zero, Ez is zero.
In this situation, the the dipole is along x-axis(phase = 0, theta = 0, phi = 0). I use a monitor of 2D-Z normal to get the electric field. I can get Ex and Ey component are zero, Ez is not zero.
I don’t quite understand why it is like this. In each situation, what’s the plane of the dipole?
In the first and second situations, two component are not zero. But there is only one non-zero component Ez in the last situation. What is the reason? Could you give me the detailed explanation of the electric field generated by the dipole source? I have read the information about the dipole source on KB but I still can not get the answer by myself. Thanks a lot.
one small question:
Why it is equivalent using “set(“phi”,45)” and “set(“angle”,45)” when setting the dipole?