Material Interface does not allow to add new materials

[g.w.castellanosgonza]

Hi all,

I would like to know if there is some criteria when defining a new material, since when I define the material interface, for example, gold-organic layer-fluid DEVICE does not allow me to add the new material created to the set of interfaces with gold.

I also tried to define a solid water material as insulator and again I was not able to add this material to the set of interfaces with gold.

Is there a reason for this? Can I create organic materials (insulator or semiconductor)?

Thanks!

[bkhanaliloo]

Dear @g.w.castellanosgonza

For heat solver you don’t need to define the solid-solid interface as software automatically does this. For a similar topic, please refer to this post:

Photothermal heating: dipole diapolo antenna example

Dear @abeer.al-mohtar No! the solid boundaries are predefined by heat equations and software does not need (and won’t allow you) to define these boundaries. In simple word, you need to specify BC for the simulation region and objects, and objects-air interface. I hope I could answer your question.

I also tried to define a solid water material as insulator and again I was not able to add this material to the set of interfaces with gold.

You can define material interface between solid and fluid objects but I think since you defined water as solid, software will not allow you to define such an interface.

I hope this answered your question.

Thanks

[g.w.castellanosgonza]

For heat solver you don’t need to define the solid-solid interface as software automatically does this. For a similar topic, please refer to this post:

photothermal heating: dipole diapolo antenna example

Thanks for your response,

In this case then I only need to define the boundary conditions at the end of the simulation region right?

[bkhanaliloo]

Dear @g.w.castellanosgonza

Yes, if there is not any fluid object or solver/solid interface:

The webinar linked below should be a very good place to learn more about heat solver and boundary settings.

https://www.lumerical.com/support/video/photothermal_heating.html

Thanks

[g.w.castellanosgonza]

Thanks for the quick reply

I watched the tutorial but I have some questions. So I have to define the boundaries as said before.

Let’s say my simulation region a 3D solid. Do I have to define them for every coordinate (-x,+x,-y … and so on)?

Additionally, if the solid extends beyond the simulation region, do I have to go always for a solid/solver boundary?

Regards,

Gabriel

[bkhanaliloo]

Dear @g.w.castellanosgonza

Let’s say my simulation region a 3D solid. Do I have to define them for every coordinate (-x,+x,-y … and so on)?

By default boundary conditions are assumed to be insulating, unless you set them to something else. This means that you do not need to define a BC if they are insulated.

Additionally, if the solid extends beyond the simulation region, do I have to go always for a solid/solver boundary?

The solver boundary will be applied to the solid. So, for example, if solver is connected to a bath, all the objects touching the solver will be connected to bath. If you define a new solid/solver BC, it will override the solver BC which means that you can define different BCs for solids on the solver boundary.

You can take a look at this post as well:

Insulating boundary condition in HEAT solver

There are quite a few ways to implement an insulating boundary condition in the HEAT solver. Some of these options are listed below, At solver boundary: If there are no boundary conditions defined at a solver boundary then that boundary is considered to be insulating by default. Alternatively, you can also define a thermal boundary condition at a solver boundary and set the model to "insulating". At solid - solver boundary intersection If you have multiple (layers of) solids at a sol…

I hope this answered your questions.

[g.w.castellanosgonza]

Yes! That helped me to understand better DEVICE. Thank you very much!

[bkhanaliloo]

Dear @g.w.castellanosgonza

I am glad that it was helpful.

Thanks