I’m trying to simulate the fifth step of the Ring Modulator Example which is in INTERCONNECT. But I’m confused about how the length of the ring is partitioned between the arms/waveguides.
For example in the ring resonator, given in the link below, the overall length of the ring (2pir) is divided in two for both arms, so that the arms have equal length. Also, note that this ring has a smaller radius than the modulator example.
But in the modulator example, the length is not equally divided.
I noticed that the Passive_Bent and the Active_Bent_0V waveguides’ lengths add up to the total length of the ring which is 10pi2 um.
1- Why isn’t the length of these waveguide’s equal and half the total length of the ring?
2- What part of the ring does the Active_Bent_modulated waveguide define? (This shouldn’t be a racetrack structure; as far as I know, this a perfect ring modulator since all of the preceding calculations in FDTD, MODE, CHARGE assumed a perfect ring.)
3- Is there a specific reason why the Active_Bent_Modulated and the Active_Bent_0V waveguides are equal in length?
4- Let’s say I want to simulate a ring modulator with radius R how should I define it for INTERCONNECT? (I had no issues with the other solvers since they had direct radius definitions.)